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12113131030000 = 2454711131210103
BaseRepresentation
bin1011000001000100111011…
…0111110100010111110000
31120220000002221001212212121
42300101032313310113300
53041430143020430000
641432410124404024
72360100451626220
oct260211667642760
946800087055777
1012113131030000
113950171750110
1214377330a6614
1369b35678a560
142dc3c8956080
15160154d40b1a
hexb044edf45f0

12113131030000 has 400 divisors, whose sum is σ = 39376280756736. Its totient is φ = 3485093760000.

The previous prime is 12113131029997. The next prime is 12113131030001. The reversal of 12113131030000 is 3013131121.

12113131030000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a tau number, because it is divible by the number of its divisors (400).

It is a Harshad number since it is a multiple of its sum of digits (16).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12113131030001) by changing a digit.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 9404949 + ... + 10615051.

Almost surely, 212113131030000 is an apocalyptic number.

12113131030000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12113131030000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19688140378368).

12113131030000 is an abundant number, since it is smaller than the sum of its proper divisors (27263149726736).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12113131030000 is a wasteful number, since it uses less digits than its factorization.

12113131030000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1210162 (or 1210141 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 12113131030000 its reverse (3013131121), we get a palindrome (12116144161121).

The spelling of 12113131030000 in words is "twelve trillion, one hundred thirteen billion, one hundred thirty-one million, thirty thousand".