Base | Representation |
---|---|
bin | 10001101000001110100… |
… | …000010110101101010000 |
3 | 11021210220020020120001220 |
4 | 101220032200112231100 |
5 | 124321444034440422 |
6 | 2324304235325040 |
7 | 153344135201664 |
oct | 21501640265520 |
9 | 4253806216056 |
10 | 1211424140112 |
11 | 4278423886aa |
12 | 1769475b0780 |
13 | 8a310356624 |
14 | 428c18848a4 |
15 | 217a2b0ae5c |
hex | 11a0e816b50 |
1211424140112 has 80 divisors (see below), whose sum is σ = 3403158201792. Its totient is φ = 369782876160.
The previous prime is 1211424140099. The next prime is 1211424140131. The reversal of 1211424140112 is 2110414241121.
It is a super-3 number, since 3×12114241401123 (a number of 37 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 20031814 + ... + 20092197.
Almost surely, 21211424140112 is an apocalyptic number.
1211424140112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1211424140112 is an abundant number, since it is smaller than the sum of its proper divisors (2191734061680).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1211424140112 is a wasteful number, since it uses less digits than its factorization.
1211424140112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 40124076 (or 40124070 counting only the distinct ones).
The product of its (nonzero) digits is 512, while the sum is 24.
Adding to 1211424140112 its reverse (2110414241121), we get a palindrome (3321838381233).
The spelling of 1211424140112 in words is "one trillion, two hundred eleven billion, four hundred twenty-four million, one hundred forty thousand, one hundred twelve".
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