Base | Representation |
---|---|
bin | 11011100100000000000010… |
… | …100111111111101000110101 |
3 | 120220012122002220220120211122 |
4 | 123210000002213333220311 |
5 | 111342042004424013023 |
6 | 1105452130112313325 |
7 | 34350641236341611 |
oct | 3344000247775065 |
9 | 526178086816748 |
10 | 121221201001013 |
11 | 3569669380a143 |
12 | 11719592b42845 |
13 | 5284158174299 |
14 | 21d11cd190341 |
15 | e033957442c8 |
hex | 6e40029ffa35 |
121221201001013 has 2 divisors, whose sum is σ = 121221201001014. Its totient is φ = 121221201001012.
The previous prime is 121221201000973. The next prime is 121221201001031. The reversal of 121221201001013 is 310100102122121.
It is a happy number.
Together with next prime (121221201001031) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 115574389805809 + 5646811195204 = 10750553^2 + 2376302^2 .
It is a cyclic number.
It is not a de Polignac number, because 121221201001013 - 226 = 121221133892149 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 121221201000982 and 121221201001000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121221201001063) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60610600500506 + 60610600500507.
It is an arithmetic number, because the mean of its divisors is an integer number (60610600500507).
Almost surely, 2121221201001013 is an apocalyptic number.
It is an amenable number.
121221201001013 is a deficient number, since it is larger than the sum of its proper divisors (1).
121221201001013 is an equidigital number, since it uses as much as digits as its factorization.
121221201001013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 121221201001013 its reverse (310100102122121), we get a palindrome (431321303123134).
The spelling of 121221201001013 in words is "one hundred twenty-one trillion, two hundred twenty-one billion, two hundred one million, one thousand, thirteen".
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