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121300210002132 = 22327598158475249
BaseRepresentation
bin11011100101001001100111…
…111011011010100011010100
3120220111012001012021200221100
4123211021213323122203110
5111344340312230032012
61105552314105350100
734356436165641630
oct3345114773324324
9526435035250840
10121300210002132
1135717148290087
1211730962a98330
13528b739ba0c15
1421d4d66481dc0
15e0546bc0d8dc
hex6e5267eda8d4

121300210002132 has 72 divisors (see below), whose sum is σ = 356362198920000. Its totient is φ = 34069792635648.

The previous prime is 121300210002131. The next prime is 121300210002137. The reversal of 121300210002132 is 231200012003121.

121300210002132 is a `hidden beast` number, since 1 + 21 + 300 + 210 + 0 + 0 + 2 + 132 = 666.

It is a super-2 number, since 2×1213002100021322 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (121300210002131) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 4079222757 + ... + 4079252492.

It is an arithmetic number, because the mean of its divisors is an integer number (4949474985000).

Almost surely, 2121300210002132 is an apocalyptic number.

121300210002132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

121300210002132 is an abundant number, since it is smaller than the sum of its proper divisors (235061988917868).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

121300210002132 is a wasteful number, since it uses less digits than its factorization.

121300210002132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8158475325 (or 8158475320 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 121300210002132 its reverse (231200012003121), we get a palindrome (352500222005253).

The spelling of 121300210002132 in words is "one hundred twenty-one trillion, three hundred billion, two hundred ten million, two thousand, one hundred thirty-two".

Divisors: 1 2 3 4 6 7 9 12 14 18 21 28 36 42 59 63 84 118 126 177 236 252 354 413 531 708 826 1062 1239 1652 2124 2478 3717 4956 7434 14868 8158475249 16316950498 24475425747 32633900996 48950851494 57109326743 73426277241 97901702988 114218653486 146852554482 171327980229 228437306972 293705108964 342655960458 481350039691 513983940687 685311920916 962700079382 1027967881374 1444050119073 1925400158764 2055935762748 2888100238146 3369450277837 4332150357219 5776200476292 6738900555674 8664300714438 10108350833511 13477801111348 17328601428876 20216701667022 30325052500533 40433403334044 60650105001066 121300210002132