Base | Representation |
---|---|
bin | 10110100110000001… |
… | …01010001110001111 |
3 | 1011022100220221011002 |
4 | 23103000222032033 |
5 | 144320301200421 |
6 | 5323354050515 |
7 | 606411102233 |
oct | 132300521617 |
9 | 34270827132 |
10 | 12130100111 |
11 | 5165141828 |
12 | 2426419a3b |
13 | 11b40b6a3c |
14 | 8310065c3 |
15 | 4aedbdb0b |
hex | 2d302a38f |
12130100111 has 4 divisors (see below), whose sum is σ = 12657495792. Its totient is φ = 11602704432.
The previous prime is 12130100071. The next prime is 12130100119. The reversal of 12130100111 is 11100103121.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12130100111 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12130100092 and 12130100101.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12130100119) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 263697806 + ... + 263697851.
It is an arithmetic number, because the mean of its divisors is an integer number (3164373948).
Almost surely, 212130100111 is an apocalyptic number.
12130100111 is a deficient number, since it is larger than the sum of its proper divisors (527395681).
12130100111 is an equidigital number, since it uses as much as digits as its factorization.
12130100111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 527395680.
The product of its (nonzero) digits is 6, while the sum is 11.
Adding to 12130100111 its reverse (11100103121), we get a palindrome (23230203232).
The spelling of 12130100111 in words is "twelve billion, one hundred thirty million, one hundred thousand, one hundred eleven".
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