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12131212111200 = 25325271337500413
BaseRepresentation
bin1011000010001000010010…
…0101101010110101100000
31120221201210000210222101200
42300202010211222311200
53042224210300024300
641445000225001200
72361310513366530
oct260420445526540
946851700728350
1012131212111200
1139578aaa82026
12143b13a483200
1369cc78739380
142dd22204b4c0
151608623b3200
hexb088496ad60

12131212111200 has 864 divisors, whose sum is σ = 54072527011776. Its totient is φ = 2490370375680.

The previous prime is 12131212111099. The next prime is 12131212111211. The reversal of 12131212111200 is 211121213121.

It is a happy number.

12131212111200 is a `hidden beast` number, since 1 + 21 + 312 + 1 + 211 + 120 + 0 = 666.

It is a super-2 number, since 2×121312121112002 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 23992194 + ... + 24492606.

Almost surely, 212131212111200 is an apocalyptic number.

12131212111200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12131212111200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (27036263505888).

12131212111200 is an abundant number, since it is smaller than the sum of its proper divisors (41941314900576).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12131212111200 is a wasteful number, since it uses less digits than its factorization.

12131212111200 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 500496 (or 500480 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 18.

Adding to 12131212111200 its reverse (211121213121), we get a palindrome (12342333324321).

The spelling of 12131212111200 in words is "twelve trillion, one hundred thirty-one billion, two hundred twelve million, one hundred eleven thousand, two hundred".