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12133011000 = 23353113371091
BaseRepresentation
bin10110100110010111…
…10000111000111000
31011022120101211010210
423103023300320320
5144322022323000
65323540311120
7606444614625
oct132313607070
934276354123
1012133011000
11516684a820
1224273a24a0
1311b4895966
1483156334c
154b0296350
hex2d32f0e38

12133011000 has 256 divisors, whose sum is σ = 41456862720. Its totient is φ = 2929920000.

The previous prime is 12133010951. The next prime is 12133011001. The reversal of 12133011000 is 11033121.

12133011000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×121330110002 (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12133011001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 11120455 + ... + 11121545.

It is an arithmetic number, because the mean of its divisors is an integer number (161940870).

Almost surely, 212133011000 is an apocalyptic number.

12133011000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12133011000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20728431360).

12133011000 is an abundant number, since it is smaller than the sum of its proper divisors (29323851720).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12133011000 is a wasteful number, since it uses less digits than its factorization.

12133011000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1463 (or 1449 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 12.

Adding to 12133011000 its reverse (11033121), we get a palindrome (12144044121).

The spelling of 12133011000 in words is "twelve billion, one hundred thirty-three million, eleven thousand".