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12143154243000 = 23353113111870141
BaseRepresentation
bin1011000010110100110001…
…1001010010010110111000
31120222212121022001010111110
42300231030121102112320
53042423134441234000
641454253230200320
72362212453005364
oct260551431222670
946885538033443
1012143154243000
113961978aa9440
1214415119530a0
136a112c8bc351
142dda360c42a4
15160d10a02850
hexb0b4c6525b8

12143154243000 has 256 divisors, whose sum is σ = 42664139182080. Its totient is φ = 2848833600000.

The previous prime is 12143154242993. The next prime is 12143154243041. The reversal of 12143154243000 is 34245134121.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 4912071 + ... + 6958070.

It is an arithmetic number, because the mean of its divisors is an integer number (166656793680).

Almost surely, 212143154243000 is an apocalyptic number.

12143154243000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

12143154243000 is an abundant number, since it is smaller than the sum of its proper divisors (30520984939080).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12143154243000 is a wasteful number, since it uses less digits than its factorization.

12143154243000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11870207 (or 11870193 counting only the distinct ones).

The product of its (nonzero) digits is 11520, while the sum is 30.

Adding to 12143154243000 its reverse (34245134121), we get a palindrome (12177399377121).

The spelling of 12143154243000 in words is "twelve trillion, one hundred forty-three billion, one hundred fifty-four million, two hundred forty-three thousand".