Base | Representation |
---|---|
bin | 11011100111000101010100… |
… | …101100111010110101110100 |
3 | 120220221212212202012220001101 |
4 | 123213011110230322311310 |
5 | 111404024322020440200 |
6 | 1110133321533335444 |
7 | 34402150502244064 |
oct | 3347052454726564 |
9 | 526855782186041 |
10 | 121433031421300 |
11 | 35768506537195 |
12 | 11752650637584 |
13 | 529b116462041 |
14 | 21db5665493a4 |
15 | e08b425dd26a |
hex | 6e7154b3ad74 |
121433031421300 has 36 divisors (see below), whose sum is σ = 268481558916396. Its totient is φ = 47656736857600.
The previous prime is 121433031421283. The next prime is 121433031421309. The reversal of 121433031421300 is 3124130334121.
It can be written as a sum of positive squares in 6 ways, for example, as 11374552173924 + 110058479247376 = 3372618^2 + 10490876^2 .
It is a super-2 number, since 2×1214330314213002 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (121433031421309) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 11455941061 + ... + 11455951660.
It is an arithmetic number, because the mean of its divisors is an integer number (7457821081011).
Almost surely, 2121433031421300 is an apocalyptic number.
121433031421300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
121433031421300 is an abundant number, since it is smaller than the sum of its proper divisors (147048527495096).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
121433031421300 is a wasteful number, since it uses less digits than its factorization.
121433031421300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22911892788 (or 22911892781 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 121433031421300 its reverse (3124130334121), we get a palindrome (124557161755421).
The spelling of 121433031421300 in words is "one hundred twenty-one trillion, four hundred thirty-three billion, thirty-one million, four hundred twenty-one thousand, three hundred".
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