Base | Representation |
---|---|
bin | 1011000010110101010111… |
… | …0110111011111100001100 |
3 | 1120222220000100210100111011 |
4 | 2300231111312323330030 |
5 | 3042424001112313234 |
6 | 41454321101135004 |
7 | 2362216421342260 |
oct | 260552566737414 |
9 | 46886010710434 |
10 | 12143313010444 |
11 | 3961a4a689800 |
12 | 1441556b5a464 |
13 | 6a115676aa95 |
14 | 2dda4d2120a0 |
15 | 160d1e914b64 |
hex | b0b55dbbf0c |
12143313010444 has 72 divisors (see below), whose sum is σ = 26698815063200. Its totient is φ = 4730523240960.
The previous prime is 12143313010393. The next prime is 12143313010471. The reversal of 12143313010444 is 44401031334121.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 25297582 + ... + 25773130.
Almost surely, 212143313010444 is an apocalyptic number.
12143313010444 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
12143313010444 is an abundant number, since it is smaller than the sum of its proper divisors (14555502052756).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12143313010444 is a wasteful number, since it uses less digits than its factorization.
12143313010444 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 483119 (or 483106 counting only the distinct ones).
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 12143313010444 its reverse (44401031334121), we get a palindrome (56544344344565).
The spelling of 12143313010444 in words is "twelve trillion, one hundred forty-three billion, three hundred thirteen million, ten thousand, four hundred forty-four".
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