Base | Representation |
---|---|
bin | 100100001110000… |
… | …0101101101111000 |
3 | 10010200211210201222 |
4 | 1020130011231320 |
5 | 4442110314000 |
6 | 320332331212 |
7 | 42055034513 |
oct | 11034055570 |
9 | 3120753658 |
10 | 1215323000 |
11 | 574022181 |
12 | 29b013b08 |
13 | 164a2ab48 |
14 | b759bd7a |
15 | 71a65a85 |
hex | 48705b78 |
1215323000 has 64 divisors (see below), whose sum is σ = 2855286720. Its totient is φ = 484176000.
The previous prime is 1215322993. The next prime is 1215323029. The reversal of 1215323000 is 3235121.
It is a self number, because there is not a number n which added to its sum of digits gives 1215323000.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 260690 + ... + 265310.
It is an arithmetic number, because the mean of its divisors is an integer number (44613855).
Almost surely, 21215323000 is an apocalyptic number.
1215323000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1215323000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1427643360).
1215323000 is an abundant number, since it is smaller than the sum of its proper divisors (1639963720).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1215323000 is a wasteful number, since it uses less digits than its factorization.
1215323000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4905 (or 4891 counting only the distinct ones).
The product of its (nonzero) digits is 180, while the sum is 17.
The square root of 1215323000 is about 34861.4830436113. The cubic root of 1215323000 is about 1067.1625407088.
Adding to 1215323000 its reverse (3235121), we get a palindrome (1218558121).
It can be divided in two parts, 12153 and 23000, that added together give a palindrome (35153).
The spelling of 1215323000 in words is "one billion, two hundred fifteen million, three hundred twenty-three thousand".
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