Base | Representation |
---|---|
bin | 10001101100111001110… |
… | …110110110100101001101 |
3 | 11022021212020120002022220 |
4 | 101230321312312211031 |
5 | 124412240241103141 |
6 | 2330454444325553 |
7 | 153612451004133 |
oct | 21547166664515 |
9 | 4267766502286 |
10 | 1216446425421 |
11 | 42998a326a17 |
12 | 1779095438b9 |
13 | 8a9309b8896 |
14 | 42c3a8a7753 |
15 | 219989b5766 |
hex | 11b39db694d |
1216446425421 has 4 divisors (see below), whose sum is σ = 1621928567232. Its totient is φ = 810964283612.
The previous prime is 1216446425413. The next prime is 1216446425461. The reversal of 1216446425421 is 1245246446121.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1216446425421 - 23 = 1216446425413 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1216446425461) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 202741070901 + ... + 202741070906.
It is an arithmetic number, because the mean of its divisors is an integer number (405482141808).
Almost surely, 21216446425421 is an apocalyptic number.
It is an amenable number.
1216446425421 is a deficient number, since it is larger than the sum of its proper divisors (405482141811).
1216446425421 is an equidigital number, since it uses as much as digits as its factorization.
1216446425421 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 405482141810.
The product of its digits is 368640, while the sum is 42.
The spelling of 1216446425421 in words is "one trillion, two hundred sixteen billion, four hundred forty-six million, four hundred twenty-five thousand, four hundred twenty-one".
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