Base | Representation |
---|---|
bin | 10001110001001111010… |
… | …110011111111011111111 |
3 | 11022201212200212021220111 |
4 | 101301033112133323333 |
5 | 130001304103310421 |
6 | 2332544433530451 |
7 | 154136021554264 |
oct | 21611726377377 |
9 | 4281780767814 |
10 | 1221102010111 |
11 | 430959283675 |
12 | 1787a8713a27 |
13 | 8b1c3398219 |
14 | 4315cd1326b |
15 | 21b6c587ee1 |
hex | 11c4f59feff |
1221102010111 has 2 divisors, whose sum is σ = 1221102010112. Its totient is φ = 1221102010110.
The previous prime is 1221102010103. The next prime is 1221102010159. The reversal of 1221102010111 is 1110102011221.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1221102010111 - 23 = 1221102010103 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1221102010091 and 1221102010100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1221102310111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610551005055 + 610551005056.
It is an arithmetic number, because the mean of its divisors is an integer number (610551005056).
Almost surely, 21221102010111 is an apocalyptic number.
1221102010111 is a deficient number, since it is larger than the sum of its proper divisors (1).
1221102010111 is an equidigital number, since it uses as much as digits as its factorization.
1221102010111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8, while the sum is 13.
Adding to 1221102010111 its reverse (1110102011221), we get a palindrome (2331204021332).
The spelling of 1221102010111 in words is "one trillion, two hundred twenty-one billion, one hundred two million, ten thousand, one hundred eleven".
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