Base | Representation |
---|---|
bin | 10001110001010000011… |
… | …111101101001111001111 |
3 | 11022201221000222021222222 |
4 | 101301100133231033033 |
5 | 130001324011413403 |
6 | 2332550401125555 |
7 | 154136343643556 |
oct | 21612037551717 |
9 | 4281830867888 |
10 | 1221121201103 |
11 | 4309690a10a1 |
12 | 1787b30298bb |
13 | 8b1c735733b |
14 | 431616aad9d |
15 | 21b6e0c9338 |
hex | 11c507ed3cf |
1221121201103 has 2 divisors, whose sum is σ = 1221121201104. Its totient is φ = 1221121201102.
The previous prime is 1221121201099. The next prime is 1221121201117. The reversal of 1221121201103 is 3011021211221.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1221121201103 - 22 = 1221121201099 is a prime.
It is a super-2 number, since 2×12211212011032 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1221121201163) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610560600551 + 610560600552.
It is an arithmetic number, because the mean of its divisors is an integer number (610560600552).
Almost surely, 21221121201103 is an apocalyptic number.
1221121201103 is a deficient number, since it is larger than the sum of its proper divisors (1).
1221121201103 is an equidigital number, since it uses as much as digits as its factorization.
1221121201103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 1221121201103 its reverse (3011021211221), we get a palindrome (4232142412324).
The spelling of 1221121201103 in words is "one trillion, two hundred twenty-one billion, one hundred twenty-one million, two hundred one thousand, one hundred three".
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