Base | Representation |
---|---|
bin | 11011110001001111101001… |
… | …011010111000110000010100 |
3 | 121000102122021001211001120110 |
4 | 123301033221122320300110 |
5 | 112001444411131420200 |
6 | 1111430203320403020 |
7 | 34503460513402002 |
oct | 3361175132706024 |
9 | 530378231731513 |
10 | 122131311201300 |
11 | 35a07664242065 |
12 | 11845a49016470 |
13 | 531bc193c310b |
14 | 22232891c3a72 |
15 | e1bdb064ab50 |
hex | 6f13e96b8c14 |
122131311201300 has 36 divisors (see below), whose sum is σ = 353366593743296. Its totient is φ = 32568349653600.
The previous prime is 122131311201293. The next prime is 122131311201313. The reversal of 122131311201300 is 3102113131221.
122131311201300 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 203552185036 + ... + 203552185635.
Almost surely, 2122131311201300 is an apocalyptic number.
122131311201300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
122131311201300 is an abundant number, since it is smaller than the sum of its proper divisors (231235282541996).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
122131311201300 is a wasteful number, since it uses less digits than its factorization.
122131311201300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 407104370688 (or 407104370681 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 122131311201300 its reverse (3102113131221), we get a palindrome (125233424332521).
The spelling of 122131311201300 in words is "one hundred twenty-two trillion, one hundred thirty-one billion, three hundred eleven million, two hundred one thousand, three hundred".
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