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122201300130000 = 2435471344762381
BaseRepresentation
bin11011110010010000110101…
…000101011101100011010000
3121000200022220201100000110220
4123302100311011131203100
5112004121230313130000
61111522300254153040
734511516064440550
oct3362206505354320
9530608821300426
10122201300130000
1135a3430a1620a3
12118575201b2780
1353256c14623b0
142226808557160
15e1db09cc11a0
hex6f243515d8d0

122201300130000 has 400 divisors, whose sum is σ = 485516429709696. Its totient is φ = 25783130880000.

The previous prime is 122201300129911. The next prime is 122201300130011. The reversal of 122201300130000 is 31003102221.

It is a tau number, because it is divible by the number of its divisors (400).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 19651191 + ... + 25111190.

Almost surely, 2122201300130000 is an apocalyptic number.

122201300130000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

122201300130000 is an abundant number, since it is smaller than the sum of its proper divisors (363315129579696).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

122201300130000 is a wasteful number, since it uses less digits than its factorization.

122201300130000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 44762432 (or 44762411 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 122201300130000 its reverse (31003102221), we get a palindrome (122232303232221).

The spelling of 122201300130000 in words is "one hundred twenty-two trillion, two hundred one billion, three hundred million, one hundred thirty thousand".