Base | Representation |
---|---|
bin | 111000111101010000… |
… | …0000100100110110101 |
3 | 102200201021221211220001 |
4 | 1301322200010212311 |
5 | 4000444430441432 |
6 | 132105044111301 |
7 | 11560030333024 |
oct | 1617240044665 |
9 | 380637854801 |
10 | 122314312117 |
11 | 47967271068 |
12 | 1b856995531 |
13 | b6c3800a1a |
14 | 5cc485c8bb |
15 | 32ad2529e7 |
hex | 1c7a8049b5 |
122314312117 has 2 divisors, whose sum is σ = 122314312118. Its totient is φ = 122314312116.
The previous prime is 122314312091. The next prime is 122314312147. The reversal of 122314312117 is 711213413221.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 115459962436 + 6854349681 = 339794^2 + 82791^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-122314312117 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (122314312147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61157156058 + 61157156059.
It is an arithmetic number, because the mean of its divisors is an integer number (61157156059).
Almost surely, 2122314312117 is an apocalyptic number.
It is an amenable number.
122314312117 is a deficient number, since it is larger than the sum of its proper divisors (1).
122314312117 is an equidigital number, since it uses as much as digits as its factorization.
122314312117 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2016, while the sum is 28.
Adding to 122314312117 its reverse (711213413221), we get a palindrome (833527725338).
The spelling of 122314312117 in words is "one hundred twenty-two billion, three hundred fourteen million, three hundred twelve thousand, one hundred seventeen".
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