12313511320 has 32 divisors (see below), whose sum is σ = 30224074320. Its totient is φ = 4477640320.

The previous prime is 12313511291. The next prime is 12313511339. The reversal of 12313511320 is 2311531321.

It is a super-3 number, since 3×12313511320³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (22).

It is a junction number, because it is equal to n+sod(n) for n = 12313511291 and 12313511300.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13992187 + ... + 13993066.

Almost surely, 2^12313511320 is an apocalyptic number.

12313511320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

12313511320 is an abundant number, since it is smaller than the sum of its proper divisors (17910563000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12313511320 is a wasteful number, since it uses less digits than its factorization.

12313511320 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 27985275 (or 27985271 counting only the distinct ones).

The product of its (nonzero) digits is 540, while the sum is 22.

The spelling of 12313511320 in words is "twelve billion, three hundred thirteen million, five hundred eleven thousand, three hundred twenty".