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12385211300 = 22527116724007
BaseRepresentation
bin10111000100011011…
…10101001110100100
31011222010221220220122
423202031311032210
5200331103230200
65404550021112
7615626362520
oct134215651644
934863856818
1012385211300
115286146620
122497947798
131224bc89c7
14856c52d80
154c74b2385
hex2e23753a4

12385211300 has 144 divisors (see below), whose sum is σ = 34009156608. Its totient is φ = 3802550400.

The previous prime is 12385211291. The next prime is 12385211303. The reversal of 12385211300 is 311258321.

12385211300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a self number, because there is not a number n which added to its sum of digits gives 12385211300.

It is not an unprimeable number, because it can be changed into a prime (12385211303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 503897 + ... + 527903.

Almost surely, 212385211300 is an apocalyptic number.

12385211300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12385211300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17004578304).

12385211300 is an abundant number, since it is smaller than the sum of its proper divisors (21623945308).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12385211300 is a wasteful number, since it uses less digits than its factorization.

12385211300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24106 (or 24099 counting only the distinct ones).

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 12385211300 its reverse (311258321), we get a palindrome (12696469621).

The spelling of 12385211300 in words is "twelve billion, three hundred eighty-five million, two hundred eleven thousand, three hundred".

Divisors: 1 2 4 5 7 10 11 14 20 22 25 28 35 44 50 55 67 70 77 100 110 134 140 154 175 220 268 275 308 335 350 385 469 550 670 700 737 770 938 1100 1340 1474 1540 1675 1876 1925 2345 2948 3350 3685 3850 4690 5159 6700 7370 7700 9380 10318 11725 14740 18425 20636 23450 24007 25795 36850 46900 48014 51590 73700 96028 103180 120035 128975 168049 240070 257950 264077 336098 480140 515900 528154 600175 672196 840245 1056308 1200350 1320385 1608469 1680490 1848539 2400700 2640770 3216938 3360980 3697078 4201225 5281540 6433876 6601925 7394156 8042345 8402450 9242695 11259283 13203850 16084690 16804900 17693159 18485390 22518566 26407700 32169380 35386318 36970780 40211725 45037132 46213475 56296415 70772636 80423450 88465795 92426950 112592830 123852113 160846900 176931590 184853900 225185660 247704226 281482075 353863180 442328975 495408452 562964150 619260565 884657950 1125928300 1238521130 1769315900 2477042260 3096302825 6192605650 12385211300