Base | Representation |
---|---|
bin | 10111001010010000… |
… | …10110001100111111 |
3 | 1012002112221222200000 |
4 | 23211020112030333 |
5 | 200431112331101 |
6 | 5413454005343 |
7 | 620062102266 |
oct | 134510261477 |
9 | 35075858600 |
10 | 12434105151 |
11 | 5300801266 |
12 | 24b01a6853 |
13 | 1232087790 |
14 | 85d53d5dd |
15 | 4cb91e486 |
hex | 2e521633f |
12434105151 has 48 divisors (see below), whose sum is σ = 20079381504. Its totient is φ = 7643722464.
The previous prime is 12434105149. The next prime is 12434105171. The reversal of 12434105151 is 15150143421.
12434105151 is a `hidden beast` number, since 1 + 243 + 410 + 5 + 1 + 5 + 1 = 666.
It is not a de Polignac number, because 12434105151 - 21 = 12434105149 is a prime.
It is a super-2 number, since 2×124341051512 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12434105171) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 4696110 + ... + 4698756.
It is an arithmetic number, because the mean of its divisors is an integer number (418320448).
Almost surely, 212434105151 is an apocalyptic number.
12434105151 is a deficient number, since it is larger than the sum of its proper divisors (7645276353).
12434105151 is a wasteful number, since it uses less digits than its factorization.
12434105151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4162 (or 4150 counting only the distinct ones).
The product of its (nonzero) digits is 2400, while the sum is 27.
Adding to 12434105151 its reverse (15150143421), we get a palindrome (27584248572).
The spelling of 12434105151 in words is "twelve billion, four hundred thirty-four million, one hundred five thousand, one hundred fifty-one".
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