Base | Representation |
---|---|
bin | 10010001110010101000… |
… | …000100111100000010111 |
3 | 11102201111102002102220110 |
4 | 102032111000213200113 |
5 | 131004240333401020 |
6 | 2355152010534103 |
7 | 156323016455220 |
oct | 22162500474027 |
9 | 4381442072813 |
10 | 1252335450135 |
11 | 443126793420 |
12 | 182864737333 |
13 | 91130162493 |
14 | 448830b4247 |
15 | 228996058e0 |
hex | 12395027817 |
1252335450135 has 64 divisors (see below), whose sum is σ = 2499717749760. Its totient is φ = 520127662080.
The previous prime is 1252335450133. The next prime is 1252335450187. The reversal of 1252335450135 is 5310545332521.
It is not a de Polignac number, because 1252335450135 - 21 = 1252335450133 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1252335450093 and 1252335450102.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1252335450133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1526911 + ... + 2199119.
It is an arithmetic number, because the mean of its divisors is an integer number (39058089840).
Almost surely, 21252335450135 is an apocalyptic number.
1252335450135 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1252335450135 is a deficient number, since it is larger than the sum of its proper divisors (1247382299625).
1252335450135 is a wasteful number, since it uses less digits than its factorization.
1252335450135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 673848.
The product of its (nonzero) digits is 270000, while the sum is 39.
The spelling of 1252335450135 in words is "one trillion, two hundred fifty-two billion, three hundred thirty-five million, four hundred fifty thousand, one hundred thirty-five".
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