Base | Representation |
---|---|
bin | 10010010110110101100… |
… | …010011111010100011000 |
3 | 11110121002002111022120011 |
4 | 102112311202133110120 |
5 | 131131443102310000 |
6 | 2403302320211304 |
7 | 160065300505036 |
oct | 22266542372430 |
9 | 4417062438504 |
10 | 1261471135000 |
11 | 446a946296aa |
12 | 184594169b34 |
13 | 91c57a6b97b |
14 | 450ac529556 |
15 | 22c316852ba |
hex | 125b589f518 |
1261471135000 has 40 divisors (see below), whose sum is σ = 2955626881020. Its totient is φ = 504588452000.
The previous prime is 1261471134991. The next prime is 1261471135039. The reversal of 1261471135000 is 5311741621.
It is a tau number, because it is divible by the number of its divisors (40).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 126142114 + ... + 126152113.
Almost surely, 21261471135000 is an apocalyptic number.
1261471135000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1261471135000 is an abundant number, since it is smaller than the sum of its proper divisors (1694155746020).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1261471135000 is an equidigital number, since it uses as much as digits as its factorization.
1261471135000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 252294253 (or 252294234 counting only the distinct ones).
The product of its (nonzero) digits is 5040, while the sum is 31.
Adding to 1261471135000 its reverse (5311741621), we get a palindrome (1266782876621).
The spelling of 1261471135000 in words is "one trillion, two hundred sixty-one billion, four hundred seventy-one million, one hundred thirty-five thousand".
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