Base | Representation |
---|---|
bin | 1011101001001111110101… |
… | …1101000001101101010100 |
3 | 1200022222102211200011001001 |
4 | 2322103331131001231110 |
5 | 3134232031211140100 |
6 | 43121422315513044 |
7 | 2461001406030124 |
oct | 272237535015524 |
9 | 50288384604031 |
10 | 12803254786900 |
11 | 4096914602126 |
12 | 1529434158784 |
13 | 71b459a7ac66 |
14 | 323976310c84 |
15 | 173096d33d6a |
hex | ba4fd741b54 |
12803254786900 has 72 divisors (see below), whose sum is σ = 29270698916480. Its totient is φ = 4847550935040.
The previous prime is 12803254786871. The next prime is 12803254786901. The reversal of 12803254786900 is 968745230821.
It is a super-2 number, since 2×128032547869002 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12803254786901) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 731484 + ... + 5112883.
It is a 1-persistent number, because it is pandigital, but 2⋅12803254786900 = 25606509573800 is not.
Almost surely, 212803254786900 is an apocalyptic number.
12803254786900 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
12803254786900 is an abundant number, since it is smaller than the sum of its proper divisors (16467444129580).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12803254786900 is a wasteful number, since it uses less digits than its factorization.
12803254786900 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5845553 (or 5845546 counting only the distinct ones).
The product of its (nonzero) digits is 5806080, while the sum is 55.
The spelling of 12803254786900 in words is "twelve trillion, eight hundred three billion, two hundred fifty-four million, seven hundred eighty-six thousand, nine hundred".
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