Base | Representation |
---|---|
bin | 10010110111111110011… |
… | …100000101111000101100 |
3 | 11120222220220210202012021 |
4 | 102313332130011320230 |
5 | 132222331301324400 |
6 | 2431505223115524 |
7 | 162465130344142 |
oct | 22677634057054 |
9 | 4528826722167 |
10 | 1297053933100 |
11 | 460094149562 |
12 | 18b4648a2ba4 |
13 | 954089475a3 |
14 | 46ac61c1592 |
15 | 23b1548671a |
hex | 12dfe705e2c |
1297053933100 has 36 divisors (see below), whose sum is σ = 2829190533064. Its totient is φ = 516133370880.
The previous prime is 1297053933079. The next prime is 1297053933127. The reversal of 1297053933100 is 13393507921.
It is a super-4 number, since 4×12970539331004 (a number of 50 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 33583134 + ... + 33621733.
Almost surely, 21297053933100 is an apocalyptic number.
1297053933100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1297053933100 is an abundant number, since it is smaller than the sum of its proper divisors (1532136599964).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1297053933100 is a wasteful number, since it uses less digits than its factorization.
1297053933100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 67205074 (or 67205067 counting only the distinct ones).
The product of its (nonzero) digits is 153090, while the sum is 43.
The spelling of 1297053933100 in words is "one trillion, two hundred ninety-seven billion, fifty-three million, nine hundred thirty-three thousand, one hundred".
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