Search a number
-
+
13000001141 is a prime number
BaseRepresentation
bin11000001101101110…
…00100011001110101
31020112222210111000202
430012313010121311
5203111000014031
65545551050245
7640103120651
oct140667043165
936488714022
1013000001141
1155711862a6
122629810985
1312c23a238a
148b4769a61
155114522cb
hex306dc4675

13000001141 has 2 divisors, whose sum is σ = 13000001142. Its totient is φ = 13000001140.

The previous prime is 13000001117. The next prime is 13000001213. The reversal of 13000001141 is 14110000031.

13000001141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6767530225 + 6232470916 = 82265^2 + 78946^2 .

It is an emirp because it is prime and its reverse (14110000031) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13000001141 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13000000141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500000570 + 6500000571.

It is an arithmetic number, because the mean of its divisors is an integer number (6500000571).

Almost surely, 213000001141 is an apocalyptic number.

It is an amenable number.

13000001141 is a deficient number, since it is larger than the sum of its proper divisors (1).

13000001141 is an equidigital number, since it uses as much as digits as its factorization.

13000001141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 13000001141 its reverse (14110000031), we get a palindrome (27110001172).

The spelling of 13000001141 in words is "thirteen billion, one thousand, one hundred forty-one".