1300000423 has 2 divisors, whose sum is σ = 1300000424. Its totient is φ = 1300000422.

The previous prime is 1300000399. The next prime is 1300000447. The reversal of 1300000423 is 3240000031.

It is a balanced prime because it is at equal distance from previous prime (1300000399) and next prime (1300000447).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1300000423 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1301000423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650000211 + 650000212.

It is an arithmetic number, because the mean of its divisors is an integer number (650000212).

Almost surely, 2^1300000423 is an apocalyptic number.

1300000423 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300000423 is an equidigital number, since it uses as much as digits as its factorization.

1300000423 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 13.

The square root of 1300000423 is about 36055.5186205940. The cubic root of 1300000423 is about 1091.3930014352.

Adding to 1300000423 its reverse (3240000031), we get a palindrome (4540000454).

The spelling of 1300000423 in words is "one billion, three hundred million, four hundred twenty-three", and thus it is an aban number.