130000441120 has 96 divisors (see below), whose sum is σ = 352680713280. Its totient is φ = 44784829440.

The previous prime is 130000441111. The next prime is 130000441121. The reversal of 130000441120 is 21144000031.

It is a super-2 number, since 2×130000441120² (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (16).

It is a junction number, because it is equal to n+sod(n) for n = 130000441094 and 130000441103.

It is not an unprimeable number, because it can be changed into a prime (130000441121) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1910347 + ... + 1977226.

It is an arithmetic number, because the mean of its divisors is an integer number (3673757430).

Almost surely, 2^130000441120 is an apocalyptic number.

130000441120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

130000441120 is an abundant number, since it is smaller than the sum of its proper divisors (222680272160).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130000441120 is a wasteful number, since it uses less digits than its factorization.

130000441120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3887618 (or 3887610 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 16.

Adding to 130000441120 its reverse (21144000031), we get a palindrome (151144441151).

The spelling of 130000441120 in words is "one hundred thirty billion, four hundred forty-one thousand, one hundred twenty".