Base | Representation |
---|---|
bin | 11101100011110010101111… |
… | …011011000110010111111000 |
3 | 122001022011111111221100011110 |
4 | 131203302233123012113320 |
5 | 114014432132341411440 |
6 | 1140254320530000320 |
7 | 36245256600564660 |
oct | 3543625733062770 |
9 | 561264444840143 |
10 | 130003013232120 |
11 | 38471a71886106 |
12 | 126b75561160a0 |
13 | 5770301920482 |
14 | 241627244b1a0 |
15 | 1006a23da3080 |
hex | 763caf6c65f8 |
130003013232120 has 128 divisors (see below), whose sum is σ = 445798028759040. Its totient is φ = 29710080322560.
The previous prime is 130003013232107. The next prime is 130003013232149. The reversal of 130003013232120 is 21232310300031.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7640776 + ... + 17843415.
It is an arithmetic number, because the mean of its divisors is an integer number (3482797099680).
Almost surely, 2130003013232120 is an apocalyptic number.
130003013232120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
130003013232120 is an abundant number, since it is smaller than the sum of its proper divisors (315795015526920).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130003013232120 is a wasteful number, since it uses less digits than its factorization.
130003013232120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25490285 (or 25490281 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 130003013232120 its reverse (21232310300031), we get a palindrome (151235323532151).
The spelling of 130003013232120 in words is "one hundred thirty trillion, three billion, thirteen million, two hundred thirty-two thousand, one hundred twenty".
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