130003110 has 64 divisors (see below), whose sum is σ = 349824960. Its totient is φ = 34352640.

The previous prime is 130003103. The next prime is 130003121. The reversal of 130003110 is 11300031.

It is a Harshad number since it is a multiple of its sum of digits (9).

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 130003092 and 130003101.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 28380 + ... + 32640.

It is an arithmetic number, because the mean of its divisors is an integer number (5466015).

Almost surely, 2^130003110 is an apocalyptic number.

130003110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 130003110, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (174912480).

130003110 is an abundant number, since it is smaller than the sum of its proper divisors (219821850).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130003110 is a wasteful number, since it uses less digits than its factorization.

130003110 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4390 (or 4384 counting only the distinct ones).

The product of its (nonzero) digits is 9, while the sum is 9.

The square root of 130003110 is about 11401.8906326977. The cubic root of 130003110 is about 506.5837415263.

Adding to 130003110 its reverse (11300031), we get a palindrome (141303141).

It can be divided in two parts, 13000 and 3110, that added together give a triangular number (16110 = T₁₇₉).

The spelling of 130003110 in words is "one hundred thirty million, three thousand, one hundred ten".