1300040023 has 8 divisors (see below), whose sum is σ = 1308917376. Its totient is φ = 1291193400.

The previous prime is 1300040003. The next prime is 1300040041. The reversal of 1300040023 is 3200400031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1300040023 - 2²⁹ = 763169111 is a prime.

It is a super-2 number, since 2×1300040023² = 3380208122803681058, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1300039985 and 1300040012.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1300040003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 80628 + ... + 95398.

It is an arithmetic number, because the mean of its divisors is an integer number (163614672).

Almost surely, 2^1300040023 is an apocalyptic number.

1300040023 is a deficient number, since it is larger than the sum of its proper divisors (8877353).

1300040023 is a wasteful number, since it uses less digits than its factorization.

1300040023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15365.

The product of its (nonzero) digits is 72, while the sum is 13.

The square root of 1300040023 is about 36056.0677695170. The cubic root of 1300040023 is about 1091.4040831557.

Adding to 1300040023 its reverse (3200400031), we get a palindrome (4500440054).

The spelling of 1300040023 in words is "one billion, three hundred million, forty thousand, twenty-three".