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13001102112120 = 2335198915446811
BaseRepresentation
bin1011110100110000111000…
…0100101011010101111000
31201000220010011022121212220
42331030032010223111320
53201002224120041440
643352342430404040
72511204300402303
oct275141604532570
951026104277786
1013001102112120
114162811227961
12155b84a960620
13733cca0c8575
1432d384553b3a
151782c62d88d0
hexbd30e12b578

13001102112120 has 64 divisors (see below), whose sum is σ = 39005274349440. Its totient is φ = 3466785628800.

The previous prime is 13001102112071. The next prime is 13001102112137. The reversal of 13001102112120 is 2121120110031.

13001102112120 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×130011021121202 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 13001102112120.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 336486 + ... + 5110325.

It is an arithmetic number, because the mean of its divisors is an integer number (609457411710).

Almost surely, 213001102112120 is an apocalyptic number.

13001102112120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13001102112120 is an abundant number, since it is smaller than the sum of its proper divisors (26004172237320).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13001102112120 is a wasteful number, since it uses less digits than its factorization.

13001102112120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5466716 (or 5466712 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 13001102112120 its reverse (2121120110031), we get a palindrome (15122222222151).

The spelling of 13001102112120 in words is "thirteen trillion, one billion, one hundred two million, one hundred twelve thousand, one hundred twenty".

Divisors: 1 2 3 4 5 6 8 10 12 15 20 24 30 40 60 120 19891 39782 59673 79564 99455 119346 159128 198910 238692 298365 397820 477384 596730 795640 1193460 2386920 5446811 10893622 16340433 21787244 27234055 32680866 43574488 54468110 65361732 81702165 108936220 130723464 163404330 217872440 326808660 653617320 108342517601 216685035202 325027552803 433370070404 541712588005 650055105606 866740140808 1083425176010 1300110211212 1625137764015 2166850352020 2600220422424 3250275528030 4333700704040 6500551056060 13001102112120