Base | Representation |
---|---|
bin | 111100100010101000… |
… | …1000100011000111100 |
3 | 110102120200212021001120 |
4 | 1321011101010120330 |
5 | 4112230321334322 |
6 | 135420513310540 |
7 | 12251540203500 |
oct | 1710521043074 |
9 | 412520767046 |
10 | 130011121212 |
11 | 50156985715 |
12 | 21244565450 |
13 | c34c29982b |
14 | 6414b62300 |
15 | 35add0da5c |
hex | 1e4544463c |
130011121212 has 72 divisors (see below), whose sum is σ = 368230294656. Its totient is φ = 35530985952.
The previous prime is 130011121181. The next prime is 130011121213. The reversal of 130011121212 is 212121110031.
It is a junction number, because it is equal to n+sod(n) for n = 130011121191 and 130011121200.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130011121213) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 4793158 + ... + 4820205.
It is an arithmetic number, because the mean of its divisors is an integer number (5114309648).
Almost surely, 2130011121212 is an apocalyptic number.
130011121212 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
130011121212 is an abundant number, since it is smaller than the sum of its proper divisors (238219173444).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130011121212 is a wasteful number, since it uses less digits than its factorization.
130011121212 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9613407 (or 9613398 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 130011121212 its reverse (212121110031), we get a palindrome (342132231243).
The spelling of 130011121212 in words is "one hundred thirty billion, eleven million, one hundred twenty-one thousand, two hundred twelve".
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