13001210003101 has 4 divisors (see below), whose sum is σ = 13122716638752. Its totient is φ = 12879703367452.

The previous prime is 13001210003039. The next prime is 13001210003107. The reversal of 13001210003101 is 10130001210031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13001210003101 - 2¹¹ = 13001210001053 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13001210003107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60753317665 + ... + 60753317878.

It is an arithmetic number, because the mean of its divisors is an integer number (3280679159688).

Almost surely, 2^{13001210003101} is an apocalyptic number.

It is an amenable number.

13001210003101 is a deficient number, since it is larger than the sum of its proper divisors (121506635651).

13001210003101 is a wasteful number, since it uses less digits than its factorization.

13001210003101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 121506635650.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 13001210003101 its reverse (10130001210031), we get a palindrome (23131211213132).

The spelling of 13001210003101 in words is "thirteen trillion, one billion, two hundred ten million, three thousand, one hundred one".