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13001210003100 = 22352113939760607
BaseRepresentation
bin1011110100110001010010…
…0000001111111010011100
31201000220101200100001111010
42331030110200033322130
53201002434230044400
643352401243055220
72511210050431254
oct275142440177234
951026350301433
1013001210003100
114162867118a60
12155b87ab11510
13734016572997
1432d3949da964
151782d09eb450
hexbd31480fe9c

13001210003100 has 72 divisors (see below), whose sum is σ = 41036546492928. Its totient is φ = 3151808484800.

The previous prime is 13001210003039. The next prime is 13001210003107. The reversal of 13001210003100 is 130001210031.

13001210003100 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×130012100031002 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13001210003107) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1969877004 + ... + 1969883603.

It is an arithmetic number, because the mean of its divisors is an integer number (569952034624).

Almost surely, 213001210003100 is an apocalyptic number.

13001210003100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13001210003100 is an abundant number, since it is smaller than the sum of its proper divisors (28035336489828).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13001210003100 is a wasteful number, since it uses less digits than its factorization.

13001210003100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3939760635 (or 3939760628 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 12.

Adding to 13001210003100 its reverse (130001210031), we get a palindrome (13131211213131).

The spelling of 13001210003100 in words is "thirteen trillion, one billion, two hundred ten million, three thousand, one hundred".

Divisors: 1 2 3 4 5 6 10 11 12 15 20 22 25 30 33 44 50 55 60 66 75 100 110 132 150 165 220 275 300 330 550 660 825 1100 1650 3300 3939760607 7879521214 11819281821 15759042428 19698803035 23638563642 39397606070 43337366677 47277127284 59096409105 78795212140 86674733354 98494015175 118192818210 130012100031 173349466708 196988030350 216686833385 236385636420 260024200062 295482045525 393976060700 433373666770 520048400124 590964091050 650060500155 866747333540 1083434166925 1181928182100 1300121000310 2166868333850 2600242000620 3250302500775 4333736667700 6500605001550 13001210003100