Search a number
-
+
13001211112 = 231625151389
BaseRepresentation
bin11000001101110111…
…01011110011101000
31020120002001221210111
430012323223303220
5203111302223422
65550033024104
7640116320401
oct140673536350
936502057714
1013001211112
11557193237a
12262a0b5034
1312c2707036
148b49a29a8
155115e0a77
hex306eebce8

13001211112 has 8 divisors (see below), whose sum is σ = 24377270850. Its totient is φ = 6500605552.

The previous prime is 13001211103. The next prime is 13001211131. The reversal of 13001211112 is 21111210031.

It is a happy number.

It can be written as a sum of positive squares in only one way, i.e., 12663901156 + 337309956 = 112534^2 + 18366^2 .

It is a tau number, because it is divible by the number of its divisors (8).

It is a junction number, because it is equal to n+sod(n) for n = 13001211092 and 13001211101.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 812575687 + ... + 812575702.

Almost surely, 213001211112 is an apocalyptic number.

It is an amenable number.

13001211112 is a deficient number, since it is larger than the sum of its proper divisors (11376059738).

13001211112 is a wasteful number, since it uses less digits than its factorization.

13001211112 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1625151395 (or 1625151391 counting only the distinct ones).

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 13001211112 its reverse (21111210031), we get a palindrome (34112421143).

The spelling of 13001211112 in words is "thirteen billion, one million, two hundred eleven thousand, one hundred twelve".

Divisors: 1 2 4 8 1625151389 3250302778 6500605556 13001211112