Base | Representation |
---|---|
bin | 11101100011111100000100… |
… | …000000010100110000011100 |
3 | 122001100010100001121011010122 |
4 | 131203330010000110300130 |
5 | 114020113132141223400 |
6 | 1140303054033054112 |
7 | 36246062614524500 |
oct | 3543740400246034 |
9 | 561303301534118 |
10 | 130013022211100 |
11 | 38476238673166 |
12 | 126b948a0b7338 |
13 | 5771238432842 |
14 | 241694186a300 |
15 | 1006e0c936685 |
hex | 763f04014c1c |
130013022211100 has 54 divisors (see below), whose sum is σ = 328190014650960. Its totient is φ = 44575893327840.
The previous prime is 130013022211067. The next prime is 130013022211159. The reversal of 130013022211100 is 1112220310031.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 13266630020 + ... + 13266639819.
Almost surely, 2130013022211100 is an apocalyptic number.
130013022211100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
130013022211100 is an abundant number, since it is smaller than the sum of its proper divisors (198176992439860).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130013022211100 is a wasteful number, since it uses less digits than its factorization.
130013022211100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26533269867 (or 26533269853 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 130013022211100 its reverse (1112220310031), we get a palindrome (131125242521131).
The spelling of 130013022211100 in words is "one hundred thirty trillion, thirteen billion, twenty-two million, two hundred eleven thousand, one hundred".
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