Base | Representation |
---|---|
bin | 11101100100000010101001… |
… | …111011111000010100110100 |
3 | 122001100210121101122110210121 |
4 | 131210002221323320110310 |
5 | 114020222131330444340 |
6 | 1140310224304501324 |
7 | 36246433211514151 |
oct | 3544025173702464 |
9 | 561323541573717 |
10 | 130020101031220 |
11 | 38479240462524 |
12 | 126ba92491a844 |
13 | 5771ac5b74aba |
14 | 2417013a63228 |
15 | 10071c411e94a |
hex | 7640a9ef8534 |
130020101031220 has 48 divisors (see below), whose sum is σ = 277858573469568. Its totient is φ = 51097562052480.
The previous prime is 130020101031203. The next prime is 130020101031263. The reversal of 130020101031220 is 22130101020031.
It is a super-2 number, since 2×1300201010312202 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 130020101031194 and 130020101031203.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 216067944 + ... + 216668863.
It is an arithmetic number, because the mean of its divisors is an integer number (5788720280616).
Almost surely, 2130020101031220 is an apocalyptic number.
130020101031220 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
130020101031220 is an abundant number, since it is smaller than the sum of its proper divisors (147838472438348).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130020101031220 is a wasteful number, since it uses less digits than its factorization.
130020101031220 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 432737080 (or 432737078 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 130020101031220 its reverse (22130101020031), we get a palindrome (152150202051251).
The spelling of 130020101031220 in words is "one hundred thirty trillion, twenty billion, one hundred one million, thirty-one thousand, two hundred twenty".
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