Base | Representation |
---|---|
bin | 111100100011001110… |
… | …1110111101110010111 |
3 | 110102122002202010122001 |
4 | 1321012131313232113 |
5 | 4112301000120143 |
6 | 135422513020131 |
7 | 12252203266060 |
oct | 1710635675627 |
9 | 412562663561 |
10 | 130031254423 |
11 | 50167287034 |
12 | 2124b254647 |
13 | c3534c8785 |
14 | 64176c3567 |
15 | 35b098914d |
hex | 1e46777b97 |
130031254423 has 32 divisors (see below), whose sum is σ = 168008518656. Its totient is φ = 98004791808.
The previous prime is 130031254421. The next prime is 130031254471. The reversal of 130031254423 is 324452130031.
It is a happy number.
It is not a de Polignac number, because 130031254423 - 21 = 130031254421 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 130031254391 and 130031254400.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130031254421) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 434736 + ... + 670117.
It is an arithmetic number, because the mean of its divisors is an integer number (5250266208).
Almost surely, 2130031254423 is an apocalyptic number.
130031254423 is a deficient number, since it is larger than the sum of its proper divisors (37977264233).
130031254423 is a wasteful number, since it uses less digits than its factorization.
130031254423 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1104943.
The product of its (nonzero) digits is 8640, while the sum is 28.
Adding to 130031254423 its reverse (324452130031), we get a palindrome (454483384454).
The spelling of 130031254423 in words is "one hundred thirty billion, thirty-one million, two hundred fifty-four thousand, four hundred twenty-three".
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