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130031254423 = 71723431104853
BaseRepresentation
bin111100100011001110…
…1110111101110010111
3110102122002202010122001
41321012131313232113
54112301000120143
6135422513020131
712252203266060
oct1710635675627
9412562663561
10130031254423
1150167287034
122124b254647
13c3534c8785
1464176c3567
1535b098914d
hex1e46777b97

130031254423 has 32 divisors (see below), whose sum is σ = 168008518656. Its totient is φ = 98004791808.

The previous prime is 130031254421. The next prime is 130031254471. The reversal of 130031254423 is 324452130031.

It is a happy number.

It is not a de Polignac number, because 130031254423 - 21 = 130031254421 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130031254391 and 130031254400.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130031254421) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 434736 + ... + 670117.

It is an arithmetic number, because the mean of its divisors is an integer number (5250266208).

Almost surely, 2130031254423 is an apocalyptic number.

130031254423 is a deficient number, since it is larger than the sum of its proper divisors (37977264233).

130031254423 is a wasteful number, since it uses less digits than its factorization.

130031254423 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1104943.

The product of its (nonzero) digits is 8640, while the sum is 28.

Adding to 130031254423 its reverse (324452130031), we get a palindrome (454483384454).

The spelling of 130031254423 in words is "one hundred thirty billion, thirty-one million, two hundred fifty-four thousand, four hundred twenty-three".

Divisors: 1 7 17 23 43 119 161 301 391 731 989 2737 5117 6923 16813 117691 1104853 7733971 18782501 25411619 47508679 131477507 177881333 332560753 431997523 807647543 1092699617 3023982661 5653532801 7648897319 18575893489 130031254423