Base | Representation |
---|---|
bin | 10010111011000001001… |
… | …000010110001101011000 |
3 | 11121022100120002002201001 |
4 | 102323001020112031120 |
5 | 132301024000023300 |
6 | 2433205305034344 |
7 | 162642102206125 |
oct | 22730110261530 |
9 | 4538316062631 |
10 | 1300320314200 |
11 | 46150aa10a76 |
12 | 1900167859b4 |
13 | 9580958867b |
14 | 46d15d2974c |
15 | 23c570e816a |
hex | 12ec1216358 |
1300320314200 has 24 divisors (see below), whose sum is σ = 3023244730980. Its totient is φ = 520128125600.
The previous prime is 1300320314171. The next prime is 1300320314213. The reversal of 1300320314200 is 24130230031.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 3250800586 + ... + 3250800985.
Almost surely, 21300320314200 is an apocalyptic number.
1300320314200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1300320314200 is an abundant number, since it is smaller than the sum of its proper divisors (1722924416780).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1300320314200 is a wasteful number, since it uses less digits than its factorization.
1300320314200 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6501601587 (or 6501601578 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 1300320314200 its reverse (24130230031), we get a palindrome (1324450544231).
The spelling of 1300320314200 in words is "one trillion, three hundred billion, three hundred twenty million, three hundred fourteen thousand, two hundred".
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