Base | Representation |
---|---|
bin | 10010111011000001010… |
… | …010100110101011011100 |
3 | 11121022100202010201011221 |
4 | 102323001102212223130 |
5 | 132301030142044400 |
6 | 2433205442423124 |
7 | 162642134105362 |
oct | 22730122465334 |
9 | 4538322121157 |
10 | 1300323003100 |
11 | 461511488200 |
12 | 190017661aa4 |
13 | 95809cba534 |
14 | 46d16429632 |
15 | 23c57479c1a |
hex | 12ec14a6adc |
1300323003100 has 108 divisors (see below), whose sum is σ = 3102142594264. Its totient is φ = 472752720000.
The previous prime is 1300323003059. The next prime is 1300323003103. The reversal of 1300323003100 is 13003230031.
It is a super-2 number, since 2×13003230031002 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1300323003103) by changing a digit.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 109995190 + ... + 110007010.
Almost surely, 21300323003100 is an apocalyptic number.
1300323003100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1300323003100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1551071297132).
1300323003100 is an abundant number, since it is smaller than the sum of its proper divisors (1801819591164).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1300323003100 is a wasteful number, since it uses less digits than its factorization.
1300323003100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20948 (or 20930 counting only the distinct ones).
The product of its (nonzero) digits is 162, while the sum is 16.
Adding to 1300323003100 its reverse (13003230031), we get a palindrome (1313326233131).
1300323003100 divided by its reverse (13003230031) gives a square (100 = 102).
The spelling of 1300323003100 in words is "one trillion, three hundred billion, three hundred twenty-three million, three thousand, one hundred".
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