Base | Representation |
---|---|
bin | 11101100100001110111110… |
… | …100100000001010100000000 |
3 | 122001102001202111001022212100 |
4 | 131210032332210001110000 |
5 | 114020431230443000000 |
6 | 1140320253230230400 |
7 | 36250412121061152 |
oct | 3544167644012400 |
9 | 561361674038770 |
10 | 130033332000000 |
11 | 3848390aa52170 |
12 | 127013b7955400 |
13 | 5773124054a00 |
14 | 241790ad52ad2 |
15 | 10076ea996a00 |
hex | 7643be901500 |
130033332000000 has 4536 divisors, whose sum is σ = 581234300730720. Its totient is φ = 27675648000000.
The previous prime is 130033331999969. The next prime is 130033332000041. The reversal of 130033332000000 is 233330031.
130033332000000 is a `hidden beast` number, since 1 + 300 + 33 + 332 + 0 + 0 + 0 + 0 + 0 + 0 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 503 ways as a sum of consecutive naturals, for example, 1940795999967 + ... + 1940796000033.
Almost surely, 2130033332000000 is an apocalyptic number.
130033332000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 130033332000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (290617150365360).
130033332000000 is an abundant number, since it is smaller than the sum of its proper divisors (451200968730720).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130033332000000 is an equidigital number, since it uses as much as digits as its factorization.
130033332000000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 185 (or 130 counting only the distinct ones).
The product of its (nonzero) digits is 486, while the sum is 18.
Adding to 130033332000000 its reverse (233330031), we get a palindrome (130033565330031).
It can be divided in two parts, 1300333 and 32000000, that added together give a palindrome (33300333).
The spelling of 130033332000000 in words is "one hundred thirty trillion, thirty-three billion, three hundred thirty-two million", and thus it is an aban number.
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