13004011122400 has 144 divisors (see below), whose sum is σ = 32185082991600. Its totient is φ = 5129888092160.

The previous prime is 13004011122307. The next prime is 13004011122457. The reversal of 13004011122400 is 422111040031.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 37609506 + ... + 37953694.

It is an arithmetic number, because the mean of its divisors is an integer number (223507520775).

Almost surely, 2^{13004011122400} is an apocalyptic number.

13004011122400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13004011122400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16092541495800).

13004011122400 is an abundant number, since it is smaller than the sum of its proper divisors (19181071869200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13004011122400 is a wasteful number, since it uses less digits than its factorization.

13004011122400 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 344861 (or 344848 counting only the distinct ones).

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 13004011122400 its reverse (422111040031), we get a palindrome (13426122162431).

The spelling of 13004011122400 in words is "thirteen trillion, four billion, eleven million, one hundred twenty-two thousand, four hundred".