13004255300 has 18 divisors (see below), whose sum is σ = 28219234218. Its totient is φ = 5201702080.

The previous prime is 13004255287. The next prime is 13004255311. The reversal of 13004255300 is 355240031.

It can be written as a sum of positive squares in 3 ways, for example, as 115648516 + 12888606784 = 10754^2 + 113528^2 .

It is a super-2 number, since 2×13004255300² (a number of 21 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 65021177 + ... + 65021376.

Almost surely, 2^13004255300 is an apocalyptic number.

13004255300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13004255300 is an abundant number, since it is smaller than the sum of its proper divisors (15214978918).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13004255300 is a wasteful number, since it uses less digits than its factorization.

13004255300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 130042567 (or 130042560 counting only the distinct ones).

The product of its (nonzero) digits is 1800, while the sum is 23.

Adding to 13004255300 its reverse (355240031), we get a palindrome (13359495331).

The spelling of 13004255300 in words is "thirteen billion, four million, two hundred fifty-five thousand, three hundred".