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130043000 = 2353130043
BaseRepresentation
bin1111100000001…
…00110001111000
3100001200212110102
413300010301320
5231242334000
620523134532
73136230053
oct760046170
9301625412
10130043000
116745125a
1237674448
1320c32229
14133b1a9a
15b63b3d5
hex7c04c78

130043000 has 32 divisors (see below), whose sum is σ = 304302960. Its totient is φ = 52016800.

The previous prime is 130042993. The next prime is 130043009. The reversal of 130043000 is 340031.

It is a super-2 number, since 2×1300430002 = 33822363698000000, which contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130043009) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 64022 + ... + 66021.

Almost surely, 2130043000 is an apocalyptic number.

130043000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

130043000 is an abundant number, since it is smaller than the sum of its proper divisors (174259960).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130043000 is a wasteful number, since it uses less digits than its factorization.

130043000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 130064 (or 130050 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 11.

The square root of 130043000 is about 11403.6397698279. The cubic root of 130043000 is about 506.6355494124.

Adding to 130043000 its reverse (340031), we get a palindrome (130383031).

The spelling of 130043000 in words is "one hundred thirty million, forty-three thousand".

Divisors: 1 2 4 5 8 10 20 25 40 50 100 125 200 250 500 1000 130043 260086 520172 650215 1040344 1300430 2600860 3251075 5201720 6502150 13004300 16255375 26008600 32510750 65021500 130043000