Base | Representation |
---|---|
bin | 10010111011001011011… |
… | …110100100111001000000 |
3 | 11121022210122201212101211 |
4 | 102323023132210321000 |
5 | 132301402420214124 |
6 | 2433234425535504 |
7 | 162646310606041 |
oct | 22731336447100 |
9 | 4538718655354 |
10 | 1300493913664 |
11 | 461599a01900 |
12 | 190064944594 |
13 | 9583652b14a |
14 | 46d30dd88c8 |
15 | 23c67489e94 |
hex | 12ecb7a4e40 |
1300493913664 has 63 divisors (see below), whose sum is σ = 2836820495131. Its totient is φ = 591087981440.
The previous prime is 1300493913613. The next prime is 1300493913679. The reversal of 1300493913664 is 4663193940031.
The square root of 1300493913664 is 1140392.
It is a perfect power (a square), and thus also a powerful number.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 8 ways as a sum of consecutive naturals, for example, 100348017 + ... + 100360975.
Almost surely, 21300493913664 is an apocalyptic number.
1300493913664 is the 1140392-nd square number.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1300493913664
1300493913664 is an abundant number, since it is smaller than the sum of its proper divisors (1536326581467).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1300493913664 is an frugal number, since it uses more digits than its factorization.
1300493913664 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25952 (or 12972 counting only the distinct ones).
The product of its (nonzero) digits is 1259712, while the sum is 49.
Multiplying 1300493913664 by its sum of digits (49), we get a square (63724201769536 = 79827442).
The spelling of 1300493913664 in words is "one trillion, three hundred billion, four hundred ninety-three million, nine hundred thirteen thousand, six hundred sixty-four".
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