Base | Representation |
---|---|
bin | 1011110100111111110100… |
… | …0010111100101011001010 |
3 | 1201001021110120112020100202 |
4 | 2331033331002330223022 |
5 | 3201033432010212300 |
6 | 43354244331532202 |
7 | 2511405533035412 |
oct | 275177502745312 |
9 | 51037416466322 |
10 | 13005111413450 |
11 | 4164489394332 |
12 | 15605895ba062 |
13 | 7344b8925810 |
14 | 32d644c09642 |
15 | 17845d299ad5 |
hex | bd3fd0bcaca |
13005111413450 has 48 divisors (see below), whose sum is σ = 26053115889696. Its totient is φ = 4801356907200.
The previous prime is 13005111413431. The next prime is 13005111413453. The reversal of 13005111413450 is 5431411150031.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (13005111413453) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 4808729 + ... + 7009571.
It is an arithmetic number, because the mean of its divisors is an integer number (542773247702).
Almost surely, 213005111413450 is an apocalyptic number.
13005111413450 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13005111413450 is an abundant number, since it is smaller than the sum of its proper divisors (13048004476246).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13005111413450 is a wasteful number, since it uses less digits than its factorization.
13005111413450 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2209959 (or 2209954 counting only the distinct ones).
The product of its (nonzero) digits is 3600, while the sum is 29.
Adding to 13005111413450 its reverse (5431411150031), we get a palindrome (18436522563481).
The spelling of 13005111413450 in words is "thirteen trillion, five billion, one hundred eleven million, four hundred thirteen thousand, four hundred fifty".
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