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13005235 = 523113089
BaseRepresentation
bin110001100111…
…000110110011
3220110201211101
4301213012303
511312131420
61142425231
7215354065
oct61470663
926421741
1013005235
117383031
124432217
132904709
141a27735
15121d60a
hexc671b3

13005235 has 8 divisors (see below), whose sum is σ = 16284960. Its totient is φ = 9951744.

The previous prime is 13005233. The next prime is 13005259. The reversal of 13005235 is 53250031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13005235 - 21 = 13005233 is a prime.

It is a super-2 number, since 2×130052352 = 338272274810450, which contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (13005233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 56430 + ... + 56659.

It is an arithmetic number, because the mean of its divisors is an integer number (2035620).

Almost surely, 213005235 is an apocalyptic number.

13005235 is a deficient number, since it is larger than the sum of its proper divisors (3279725).

13005235 is a wasteful number, since it uses less digits than its factorization.

13005235 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 113117.

The product of its (nonzero) digits is 450, while the sum is 19.

The square root of 13005235 is about 3606.2771662755. The cubic root of 13005235 is about 235.1650266828.

Adding to 13005235 its reverse (53250031), we get a palindrome (66255266).

The spelling of 13005235 in words is "thirteen million, five thousand, two hundred thirty-five".

Divisors: 1 5 23 115 113089 565445 2601047 13005235