Base | Representation |
---|---|
bin | 1011110101000010110010… |
… | …1110010101111101111111 |
3 | 1201001100112022200121122222 |
4 | 2331100230232111331333 |
5 | 3201042101244142044 |
6 | 43354455544355555 |
7 | 2511434415104666 |
oct | 275205456257577 |
9 | 51040468617588 |
10 | 13005911318399 |
11 | 416485996a7aa |
12 | 1560771475bbb |
13 | 7345b557435c |
14 | 32d6bd14bddd |
15 | 1784a86038ee |
hex | bd42cb95f7f |
13005911318399 has 4 divisors (see below), whose sum is σ = 13014874732200. Its totient is φ = 12996947904600.
The previous prime is 13005911318353. The next prime is 13005911318417. The reversal of 13005911318399 is 99381311950031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13005911318399 - 236 = 12937191841663 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 13005911318399.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13005911318329) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4481704724 + ... + 4481707625.
It is an arithmetic number, because the mean of its divisors is an integer number (3253718683050).
Almost surely, 213005911318399 is an apocalyptic number.
13005911318399 is a deficient number, since it is larger than the sum of its proper divisors (8963413801).
13005911318399 is an equidigital number, since it uses as much as digits as its factorization.
13005911318399 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8963413800.
The product of its (nonzero) digits is 787320, while the sum is 53.
The spelling of 13005911318399 in words is "thirteen trillion, five billion, nine hundred eleven million, three hundred eighteen thousand, three hundred ninety-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.087 sec. • engine limits •