130089170534400 has 6144 divisors, whose sum is σ = 644823128678400. Its totient is φ = 25225592832000.

The previous prime is 130089170534381. The next prime is 130089170534443. The reversal of 130089170534400 is 4435071980031.

130089170534400 is a `hidden beast` number, since 1 + 3 + 0 + 0 + 8 + 9 + 1 + 70 + 534 + 40 + 0 = 666.

It is a tau number, because it is divible by the number of its divisors (6144).

It is a Harshad number since it is a multiple of its sum of digits (45).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 383 ways as a sum of consecutive naturals, for example, 3172906598380 + ... + 3172906598420.

It is an arithmetic number, because the mean of its divisors is an integer number (104951681100).

Almost surely, 2^{130089170534400} is an apocalyptic number.

130089170534400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130089170534400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (322411564339200).

130089170534400 is an abundant number, since it is smaller than the sum of its proper divisors (514733958144000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130089170534400 is an frugal number, since it uses more digits than its factorization.

130089170534400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 143 (or 92 counting only the distinct ones).

The product of its (nonzero) digits is 362880, while the sum is 45.

The spelling of 130089170534400 in words is "one hundred thirty trillion, eighty-nine billion, one hundred seventy million, five hundred thirty-four thousand, four hundred".