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13011011122330 = 2513195267615839
BaseRepresentation
bin1011110101010101110010…
…1100100011010010011010
31201001211200201212111111001
42331111130230203102122
53201133022321403310
643401102003055214
72512004661530014
oct275253454432232
951054621774431
1013011011122330
114166a366449a1
12156175537150a
13734c18ca8410
1432da4458d1b4
151786a61c193a
hexbd55cb2349a

13011011122330 has 32 divisors (see below), whose sum is σ = 26548783833600. Its totient is φ = 4551220084032.

The previous prime is 13011011122321. The next prime is 13011011122339. The reversal of 13011011122330 is 3322111011031.

It is an interprime number because it is at equal distance from previous prime (13011011122321) and next prime (13011011122339).

It is a Harshad number since it is a multiple of its sum of digits (19).

It is a junction number, because it is equal to n+sod(n) for n = 13011011122298 and 13011011122307.

It is not an unprimeable number, because it can be changed into a prime (13011011122339) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2633805450 + ... + 2633810389.

It is an arithmetic number, because the mean of its divisors is an integer number (829649494800).

Almost surely, 213011011122330 is an apocalyptic number.

13011011122330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13011011122330 is an abundant number, since it is smaller than the sum of its proper divisors (13537772711270).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13011011122330 is a wasteful number, since it uses less digits than its factorization.

13011011122330 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5267615878.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 13011011122330 its reverse (3322111011031), we get a palindrome (16333122133361).

The spelling of 13011011122330 in words is "thirteen trillion, eleven billion, eleven million, one hundred twenty-two thousand, three hundred thirty".

Divisors: 1 2 5 10 13 19 26 38 65 95 130 190 247 494 1235 2470 5267615839 10535231678 26338079195 52676158390 68479005907 100084700941 136958011814 200169401882 342395029535 500423504705 684790059070 1000847009410 1301101112233 2602202224466 6505505561165 13011011122330